Question

Find the point on the x-axis which is
equidistant from the points (2,-2) and​ ( -4, 2)

Answer 1

Answer:

(-1,0)

Step-by-step explanation:

Let the point be

$(x \: \: \: \: 0)$

$\sqrt{ {(x - 2)}^{2} + {(y + 2)}^{2} } = \sqrt{ {(x + 4)}^{2} + {(y - 2)}^{2} } \\ \\ \\ \\ {(x - 2)}^{2} + {(y + 2)}^{2} = {(x + 4)}^{2} + {(y - 2)}^{2} \\ \\ {(x - 2)}^{2} - {(x + 4)}^{2} = {(y - 2)}^{2} - {(y + 2)}^{2} \\ \\ ( - 2 - 4)(2x + 2) = ( - 4)(2y) \\ \\ - 6(2)(x + 1) = - 8y \\ \\ \\ - 6(x + 1) = - 4y \\ \\ \\ \\ the \: point \: lies \: on \: the \: x \: or \: axis \: or \: y = 0\\ therefore \: \: - 6(x + 1)= -0 \\ \\ or \: \: x = - 1 \: \: \: therefore \: required \: point \: is \: ( - 1 \: \: \: \: 0).$

Answer 2

Answer:

hi Anjali

Step-by-step explanation:

did u joined any social app