Question

Find the point on the X-axis which is equidistant from the points A (7,6) and
B (3, 4).​

Answer 1

Answer:

let A , B and C are the given point

there fore, AC= BC

using distance formula= √(X-x) ^(y- y )^=√(x -x)^( y

- y )^

√(x-7)^+( 0-6)^=√(x-3)^+( 0-4)^

√x^- 2x7^+49+36=√ x^-2x9+9+16

squarring both sides

x^ -14^+85= x^-18+28

x^-169+85=x^+10

x^-x^=-80+10

=-70

therefore, point on X-axis =(-70,0)