Question

find the point on the X axis which is equidistant from the point 2,-2 and -4,2​

Answer 1

Given:-

• Coordinates of point A = (2,-2)
• Coordinates of point B = (-4,2)

To find:-

• Coordinates of point on X axis which is equidistant from points A and B
• let the point be (p,0)

Formula to be used:-

$\underline{\boxed{\sf p = \dfrac{x+x'}{2}, q = \dfrac{y+y'}{2}}}$

• This formula is known as Section formula

here,

• x = 2
• x' = -4
• y = -2
• y' = 2

Solution:-

$\longrightarrow$ p = $\sf\dfrac{2+(-4)}{2}$

$\longrightarrow$ p = $\sf\dfrac{-2}{2}$ = -1

hence, the coordinates are ( -1,0 )

Additional information:-

to find distance between two points we use Distance formula:-

$\underline{\boxed{\sf distance = √(x-x')²+(y-y')² }}$