Find the point on the y-axis equidistant from ( - 5, 2) and (9, - 2)
(Hint: A point on the y-axis will have its x-coordinate as zero).
Answers
Answered by
157
let the point is (0,y)
according to question
=> √{(y-2)² + (0+5)²} = √{(y+2)² + (0-9)²}
=> (y-2)² + 25 = (y+2)² + 81 (square both side)
=> y²+4-4y = y²+4y+4+56
=> 8y = -56
=> y = -7
point = (0,-7).
according to question
=> √{(y-2)² + (0+5)²} = √{(y+2)² + (0-9)²}
=> (y-2)² + 25 = (y+2)² + 81 (square both side)
=> y²+4-4y = y²+4y+4+56
=> 8y = -56
=> y = -7
point = (0,-7).
Answered by
55
Step-by-step explanation:
hope it will help you
support me for more answers
Attachments:
Similar questions