Math, asked by ameeramohammedalansa, 9 months ago

find the point on the y axis that is equidistant from [-5,2] and [3,2]

Answers

Answered by jyotigupta64

11

Step-by-step explanation:

☜☆☞-5+3/2 and 2+

☜☆☞-2/2 and 4/2

☜☆☞-1 and 2

thus required point is (-1,2)

☜☆☞hope it helps you please mark me as brainliest please hope

Answered by achuappu066

0

Answer:

Above one is the right answer

Previous Question

Next Question

Similar questions

English, 4 months ago

how does Portia first encounter bassanio ?

India Languages, 4 months ago

"पेड़ के नीचे टोपीवाला सो गया।" इस वाक्य में कौन सा संबंधबोधक है? 1. कालवाचक II. साधन वाचक III. स्थान वाचक...

English, 4 months ago

i n the chapter the cookie theif (a) where was the cookie bag put...

History, 9 months ago

What events in Canadian history led it to its diverse culture...

Math, 9 months ago

Ahmed required 18 1/2 feet long for cable connection.he joined two length of wire 9 3/4 feet and 11 1/6 feet. Now how much lengthHe have more than required length.

English, 1 year ago

what was margie school life...

Math, 1 year ago

If non-zero real numbers b and c are such that min f(x) > max g(x), where f(x) = x² + 2bx + 2c² and g(x) = –x² – 2cx + b² (x ∈ R); then $|\frac{c}{b}|$ lies in the interval: (a) $\bigg \lgroup 0,\ \frac{1}{2}\bigg \rgroup$ (b) $\bigg [\frac{1}{2},\ \frac{1}{\sqrt{2}}\bigg \rgroup$ (c) $\bigg [\frac{1}{\sqrt{2}},\ \sqrt{2}\bigg ]$ (d) (√2,∞)...

Math, 1 year ago

If α ≠ β but α² = 5α – 3 and β² = 5β – 3 then the equation having ${\alpha}/{\beta}\ and\ {\beta}/{\alpha}$ as its roots is (a) 3x² – 19x + 3 = 0 (b) 3x² + 19x – 3 = 0 (c) 3x² – 19x – 3 = 0 (d) x² – 5x + 3 = 0.