Find the point on the y-axis which is equidistant from A(3,6) and B(−2,5)
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Question:-
Find the point on the y-axis which is equidistant from A(3,6) and B(−2,5)
Answer:-
Refer to attachment
Know more:-
- To locate the position of an object or a point in a plane, we require two perpendicular lines. One of them is horizontal and other is vertical..
- The plane is called car tesian, or coordinate axes..
- The horizontal (-) line is called x-axis and the vertical (|) line is called y-axis..
- The coordinate axes divide the plane into 4 parts called Quadrants..
- The point of intersection of axes is called origin..
- The distance of the point from the point y-axis is called x-coordinates, or abscissa..
- If the abscissa of a point is x and the ordinate is y, then (x,y)are cled coordinates of the point..
- The coordinates of origin is (0,0)
- The coordinates of a point are of the form (+, +) in first quadrat (-,+) in the second quadrat (-, -) in the third quadrant and (+, -) in the fourth quadrant, where + denotes a positive real number and - denotes a negative real number.
- If x ≠ y, then (y, x) and (x, y) =(y, x), if x=y
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