Question

Find the point on the y-axis, which is equidistant from the points A (-3, 2)
and B ( 5, -2).

Answer 1

Answer:

point on y-axixs x= 0

point=(0,y)

equidistant from (5।-2) and (-3,2)

distance from first point= (25+y^2+y-4y)^1/2

distance from second point=(9+y^2+4-4y)^1/2

both equal

squaring both

29+y^2+4y=13+y^2-4y

8y=-16

y= -2

point= (0, -2)