Question

Find the point on the y-axis whose from (3, 2) and (-1, 3) and (-1, 3/2)

are in the ratio 2 : 1
pls find the explained solution ​

Answer 1

Answer:

since point is on y axis therefore x=0

let the point be (0,'k)

dist from (3,2)=√[3-0]^2[2-k]^2=d(let)

from (-1,3/2)=√[-1]^2+[3/2-k]^2=m(let)

u can find d and m above...

Now d/m=2/1

square both sides

d^2=4m^2

Step-by-step explanation:

hope it helps u