Question

Find the point on x axis which are equidistant from (2,-5) and (-2,5)​

Answer 1

Answer:

Let point P(x,0) is on x-axis and equidustant from A(2,−5) and B(−2,9)

PA=PB

or PA

2

=PB

2

(2−x)

2

+(−5−0)

2

=(−2−x)

2

+(9−0)

2

(2−x)

2

+(−5)

2

=(−2−x)

2

+(9)

2

29+x

2

−4x=85+x

2

+4x

56=−8x

or x=−7

The point on x-axis is (−7,0).

Step-by-step explanation:

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Answer 2

Answer:

x=8

y=0

Step-by-step explanation: