Question

find the point on x axis which is equi-distant from (2,-5) & ( -2, 9) . plz solve it in complete manner ,don't give only answer.

Answer 1

X = ?, Y = 0, x1 = 2, y1 = -5, x2 = -2, y2 = 9 .
( X - x1 )^2 + ( Y - y1 )^2 = ( X - x2 )^2 + ( Y - y2 )^2 ( we have applied distance formula and cancelled the under roots)
( X - 2 )^2 + ( -5 )^2 = ( X + 2 )^2 + ( 9 )^2
X^2 + 4 - 4X + 25 = X^2 + 4 + 4X + 81
-8X = 56
X = -7.
Y = 0
( X, Y ) = ( -7, 0 ) ANSWER.
thanks...