Question

find the point on x axis which is equidistance from (3,-4) (-3,7) plz solve 50 points​

Answer 1

Step-by-step explanation:

We have to find a point on x-axis. Its y-coordinate will be 0.

Let the point be (x,0).

Given points are (3,-4) and (-3,7).

(i)

Distance between (x,0) and (3,-4)

= √(x - 3)² + (0 - (-4))²

= √(x - 3)² + (4)²

(ii)

Distance between (x,0) and (-3,7):

= √(x + 3)² + (0 - 7)²

= √(x + 3)² + (-7)²

Now,

Their distance will be equal in measure.

⇒ √(x - 3)² + 4² = √(x + 3)² + 7²

⇒ (x - 3)² + 16 = (x + 3)² + 49

⇒ x² + 9 - 6x + 16 = x² + 9 + 6x + 49

⇒ -12x = 33

⇒ x = -11/4

Therefore, the point is (-11/4,0).

Hope it helps!

Answer 2

Hope it helps ! mark as brainliest