Question

Find the point on x axis which is equidistant from (2,-5) (-2,9)

Answer 1

Step-by-step explanation:

The point is on the x axis. Hence we can assume the coordinate of the point as (h,0).

Now the point is equidistant from (2,-5) and (-2,9).

So (2-h)^{2} + (-5)^{2} = (h+2)^{2} + (-9)^{2}(2−h)2+(−5)2=(h+2)2+(−9)2

Simplifying this we get -4h + 29 = 4h + 85−4h+29=4h+85

Or 8h = -56 or h= -7

Hence the point is (-7,0) which is equidistant from (2,-5) and (-2,9).

Answer 2

Step-by-step explanation:

here if it is from x axis then y = 0

by distance formula