Find the point on x - axis which is equidistant from (2, -5) and (-2, 4)?
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Step-by-step explanation:
Atq
√(2-x)2+(0+5)2==√(x+2)2+(0-4)2
4+x2-4x+25=X2+4+4x+16
-8x=-9
X=9/8
So coordinates will be (9/8,0)
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