Question

Find the point on X-axis which is equidistant
from A(-3, 4) and B(1,4).
​

Answer 1

Answer:

PLS make my answer brilliant

Step-by-step explanation:

Let the point on the x-axis be P(a, 0).

PA=(a−(−3))2+(0−4)2

=(a+3)2+16

PB=(a−1)2+(0−(−4))2

=(a−1)2+16

PA2=PB2

⇒(a+3)2+16=(a−1)2+16

⇒a2+6a+9=a2−2a+1

⇒8a=−8

⇒a=−1

(a,0)=(−1,0)