Find the point on X axis which is equidistant from A ( -3,4) and (B 1,-4)
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if it is equidistant it means it is the mid point.
therefore let A(-3,4) be x1 y1
and B(1,-4) be x2 y2
now according to mid point theorem
x=(x1+x2)÷2
x=(-3+1)÷2
x=-2÷2
x=-1
similarly;
y=(4-4)÷2
y=0÷2
y=0
therefore the point equidistant from A(-3,4)and B(1,-4) is (-1,0)
therefore let A(-3,4) be x1 y1
and B(1,-4) be x2 y2
now according to mid point theorem
x=(x1+x2)÷2
x=(-3+1)÷2
x=-2÷2
x=-1
similarly;
y=(4-4)÷2
y=0÷2
y=0
therefore the point equidistant from A(-3,4)and B(1,-4) is (-1,0)
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