Question

find the point on x axis which is equidistant from p(2,-5) & (-2,9)​

Answer 1

Answer:

point A (-7,0)

Step-by-step explanation:

since the point lies on x axis.

then it's y coordinate must be zero.

let the point be A.

therefore A(X,0)

√(2-X)²+(-5-0)²=√(X-(-2))²+(0-9)² (distance formula)

so

(2-X)²+(-5-0)²=(X-(-2))²+(0-9)²

4+X²-4X+25=X²+4+4X+81

-4X+25=4X+81

8X=25-81=56

or X=-7

therefore

answer is point A(-7,0) is equidistant to both the given points.

Hope that you are satisfied with the answer.