Question

Find the point on X–axis which is equidistant from,p(2,-5) and Q(-2,9) .​

Answer 1

$\huge  \star\rm{ \red{Solution:-}}$

Given,

The points are (2,-5) and (-2,9).

To find,

The point on the x-axis which is equidistant from the two given points.

Solution,

Now,the point is on x-axis,so the value 'y' of the given point will be zero.

Let,the value of the 'x' value of the given point = x

[Assume,x as a variable to do the further mathematical calculations.]

So,the point is = (x,0)

As mentioned in the question,the two points are equidistant from (x,0).

So,

Distance between (x,0) and (2,-5)

= ✓(x-2)²+(0+5)²

Distance between (x,0) and (-2,9).

=✓(x+2)²+(0-9)²

Now,the points are equidistant.

So,

✓(x-2)²+(0+5)² = ✓(x+2)²+(0-9)²

(x-2)²+(0+5)² = (x+2)²+(0-9)²

x²-4x+4+25 = x²+4x+4+81

x²-4x-x²-4x = 4+81-4-25

-8x = 56

x = -7

Hence,the point on x-axis is (-7,0).

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