Question

find the point on X-axis which is equidistant from P[2,-5] and Q[-2,9]

Answer 1

Answer:

Let the coordinates of the point be x and 0

(-2-x)^2+(9-0)^2=(2-x)^2+(-5-0)^2

4+x^2+4x+81=4+x^2-4x+25

4x+85=-4x+29

8x=56

x=56/8=7

coordinates of point are:7,0