Question

Find the point on x-axis which is equidistant from the points (2,-2) and (-4,2)

Friends pls give me the answer

tomorrow is my exam​

Answer 1

Answer:

(-1,0)

Step-by-step explanation:

let point be p and distance be PA and PB

PA = PB

PA²= PB²

(x - 2)² + (0 + 2)² = (x + 4)² + (0 - 2)²

x² + 4 - 4x + 4 =x² + 16 + 8x + 4

-4x + 4 = 8x + 16

x = -1

P(-1,0)