Question

find the point on x-axis which is equidistant from the points A(2,3) and B(3,7).​

Answer 1

Answer:

Hope you will understand!

Answer 2

Answer:

(-1.5,0)

Step-by-step explanation:

let's say the point C(x,y) is equidistant from the both points A and B and C is on the x axis. so y value is 0

thus, C(x,0)

the formula which shows the distance between 2 ponts is

d=root((x-x1)^2+(y-y1)^2)

the first find the distance between A and C

d1=root((2-x)^2+(3-0l)^2)

the second fint the distance between B and C

d2=root ((3-x)^2+(7-0)^2)

and we know that,

d1=d2

the degree of root is 2 and same we can ignore

(2-x)^2+9=(3-x)^2+49

collect the unknown value x to left hanf side and the known values to the right hand side

(2-x)^2-(3-x)^2=40

(there is a formula a^2-b^2=(a-b)×(a+b))

(2-x-3+x)×(2-x+3-x)=40

(5)×(5-2x)=40

25-10x=40

-15=10x

-1.5=x

Hence, location of the point C which is equidistant from A and B is (-1.5,0)

I wish you will be successful.