Math, asked by rahulp34, 5 months ago

find the point on x axis which is equidistant from the point (-2 5) and (2,9)​

Answers

Answered by MaheswariS
0

\underline{\textsf{Given:}}

\textsf{Points\;are\;(-2,5)\;and\;(2,9)}

\underline{\textsf{To find:}}

\textsf{The point on x axis which is equidistant from}

\textsf{the given two points}

\underline{\textsf{Solution:}}

\textsf{Let the given points be A(-2,5) and B(2,9)}

\textsf{Let the required point on x axis be P(h,0)}

\textsf{As per given data,}

\mathsf{PA=PB}

\mathsf{\sqrt{(h+2)^2+(0-5)^2}=\sqrt{(h-2)^2+(0-9)^2}}

\mathsf{\sqrt{(h+2)^2+25}=\sqrt{(h-2)^2+81}}

\mathsf{Squaring\;on\;bothsides\;we\;get}

\mathsf{h^2+4+4h+25=h^2+4-4h+81}

\mathsf{4h+25=-4h+81}

\mathsf{4h+4h=81-25}

\mathsf{8h=56}

\mathsf{h=\dfrac{56}{8}}

\implies\mathsf{h=7}

\underline{\textsf{Answer:}}

\textsf{The required point on x axis is (7,0)}

\underline{\textsf{Find more:}}

Find the point on y-axis which is equidistant from the points (5,- 2) and (- 3,2)

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The point on the x-axis which is equidistant from the points (6, -2) and (5, 4) is ​

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