Question

find the point on x axis which is equidistant from the point (-2 5) and (2,9)​

Answer 1

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Point on the x - axis which...

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Asked on December 30, 2019 by

Gautami Prakashini

Point on the x-axis which is equidistant from (2,−5) and (−2,9) is:

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ANSWER

Given points A(2,−5) and B(−2,9)

Let the points be P(x,0).

So, AP=PB and AP

2

=PB

2

⇒(x−2)

2

+(0+5)

2

=(x+2)

2

+(0−9)

2

⇒x

2

+4−4x+25=x

2

+4+4x+81

⇒x

2

+29−4x=x

2

+85+4x

⇒−4x−4x=85−29

⇒−8x=56

⇒x=−7

Hence, point on the x-axis which is equidistant from (2,−5) and (−2,9) is (−7,0).