Question

find the point on x axis which is equidistant from the point (2 - 2 )and (-4 2)​

Answer 1

Answer:

point p is equidistant from a and b

coordinates of a =(2,-2)

coordinates of b = (-4,2)

coordinates of p = (x,0)

pa = pb

sw.root (x-2)2+(0+2)2 = sq.root(x+4)2+(0-2)2

(x-2)2+4 = (x+4)2+4

x2+4-4x = x2+16+8x

4-4x = 16+8x

-12 = 12 x

x = -1