Question

Find the point on X axis whose distance from the line 4x +3y=12are 4 units​

Answer 1

Answer:

Step-by-step explanation:

The given equation of line is  

3

x

​  

+  

4

y

​  

=1 or 4x+3y−12=0

Let (a,0) be the point on the x-axis whose distance from the given line is 4 units.

Thus, using distance formula,

4=  

4  

2

+3  

2

 

​  

 

∣4a+3⋅0−12∣

​  

 

⇒4=  

5

∣4a−12∣

​  

 

⇒∣4a−12∣=20

⇒±(4a−12)=20

⇒(4a−12)=20or−(4a−12)=20

⇒4a=20+12or4a=−20+12

⇒a=8or−2

Thus, the required points on the x-axis are (−2,0) and (8,0)