Find the point on Y axis from where the graph of linear equation 3x= 2-5y will pass
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Hi ,
If a line intersecting with y-axis ,
to find the intersecting point on y -axis
we have to put x=0 in the given linear
equation
2x = 1 - 5y --------( 1 )
put x= 0 in equation ( 1 ) ,
2 x 0 = 1 - 5y
0 = 1 - 5y
5y = 1 [ ∵ transposing ]
y = 1/5
required point on y- axis = ( 0 , y )
= ( 0 , 1/5 )
I hope this helps you.
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