find the point on y-axis where the circle having equation x^2+y^2-5x-7y+6=0 intercept.
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actually circle intercepted y-axis so x =0
use this above equation
i.e y^2-7y+6=0
solve this quadratic equation
y^2-6y-y+6=0
( y-6)(y-1)=0
y=6,1
hence (0,1) and (0,6) are the point where intercept circle
use this above equation
i.e y^2-7y+6=0
solve this quadratic equation
y^2-6y-y+6=0
( y-6)(y-1)=0
y=6,1
hence (0,1) and (0,6) are the point where intercept circle
Sassa:
it was really helpful
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