Question

find the point on y axis which as equidistant from point (-5,-2)and (3,2)​

Answer 1

Step-by-step explanation:

Let A(5,−2) and B(−3,2). Then,

PA=PB

PA

2

=PB

2

(5−0)

2

+(−2−y)

2

=(−3−0)

2

+(2−y)

2

25+4+y

2

+4y=9+4+y

2

−4y

8y=−16

y=−2

Therefore, the required point is (0,−2).