Question

find the point on y axis which is equidistant from (- 5, 2) and (-9 -2)​

Answer 1

The point on y axis which is equidistant from (- 5, 2) and (-9 -2)​ is (0,-7).

Step-by-step explanation:

To find : The point on y axis which is equidistant from (- 5, 2) and (-9 -2)​ ?

Solution :

Let the point on y axis be (0,y) as x coordinate is 0 on y-axis.

So, the point (0,y) is equidistant from (- 5, 2) and (-9 -2).

i.e. their distance is equal.

Applying distance formula, $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$\sqrt{(0-(-5))^2+(y-2)^2}=\sqrt{(-9-0)^2+(-2-y)^2}$

$25+y^2+4-4y=81+4+y^2+4y$

$29-4y=85+4y$

$8y=-56$

$y=\frac{-56}{8}$

$y=-7$

Therefore, the point on y axis which is equidistant from (- 5, 2) and (-9 -2)​ is (0,-7).

#Learn more

Find the point of the y axis which is equidistant from the points (6,2) and (2,10)

https://brainly.in/question/6468260