Question

Find the point on y axis which is equidistant from the points (3, 4) and (6, 7)​

Answer 1

Step-by-step explanation:

Given points A(7,6) and B(-3,4)

Let the point be P(0,y) [we know that point on y-axis is (0,y)]

So, AP=PB and AP2=PB2

⇒(y-7)2+(0-6)2=(y+3)2+(0-4)2

y2+49-14y + 36=y2+9+6y + 16

49-9+36-16=6y+14y

40+20=20y

60/20=y

⇒y=3

Hence, point on x-axis which is equidistant from the points A(7,6) and B(-3,4) is (0,3).-----Ans.

Answer 2

Step-by-step explanation:

hope it will help you

thanks