Question

Find the point on y-axis which is equidistant from the points (-5, -2)&(3, 2)​

Answer 1

the point (x, y) is equidistant from the points (2, 1) and (1, ‑2), then (1 Point) x+3y= 0

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Answer 2

Answer:

⇒√(0+5)²+(y+2)²=√(0-3)²+(y-2)² (Using Distance Formula)

⇒√(25+y²+4y+4)=√(9+y²-4y+4)

⇒√(y²+4y+29)=√(y²-4y+13)

⇒y²+4y+29=y²-4y+13

⇒4y+29=13-4y

⇒8y=16

⇒y=2