Question

find the point on y axis which is equidistant from the points a(3,2,2) and b(5,5,4)

Answer 1

Answer:

0.11,.01.23.,0.243 that you are doing....

Answer 2

Answer:

thus the point is (0,7/2,0)

Step-by-step explanation:

let the point P on axis is (0,y,0)

give n points are A( 3,2,2) B(5,5,4)

PA=PB

OR PA²=PB²

(3-0²) +(2-y)²+(2-0)²=(5-0)²+(5-y)²+(4-0)²

9+4+y²+-4y+4=25+25+y²-10y+16

14y=66-17

14y=49

y=49/14=7/2

thus the point is (0,7/2,0)