Question

find the point on y axis which is equidistant from the points (5,-2)and (-3,2)

Answer 1

let suppose the point on Y axis is A
So the A(0,y)
(5,-2) = P
(-3,2)=Q
AP²= AQ²..(Equidistant point)
By distance formula
(0-5)² + [(y-(-2)]²=[(0-(-3)]² + (y-2)²
25+y²+4y+4 = 9+ y²-4y+4
4y +4y=9-25 ......(like term)
8y=-16
y=-16/8
y=-2
A(0,-2)

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Therefore the coordinates (5,-2) and (-3,2) is equidistant on Y axis at point (0,-2)

Answer 2

Answer:

A(0, y)

B(5, 2)

C(-3, 2)

AP^2=AQ^2 (equidistant)

•(0-5) ^2 +[y-(-12)]=(0-(-3)) +(y-2)

•25+y^2+4y+4=9+y^2-4y+4

•4y+4y=9-25

•8y=-16

•|"y=-2"|

Step-by-step explanation: