Find the point on y-axis,which is equidistant from the point (-2,-5) and (3,2).
*Very urgent question*
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Step-by-step explanation:
Since the point is on y-axis it's coordinates are (0,y).
If P(0,y) be the point equidistant from A(5,-2) and B(-3,2),
AP=BP Given
AP2=BP2 squaring as to remove roots.
(0-5)2+(y+2)2=
(-3-0)2+(2-y)2
=25+y2+4y+4=9+4-4y+y2
=16= -8y
So,y= -2.
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