Question

find the point on y axis which is equidistant from the point (5,-2) and (-3,2) .​

Answer 1

Answer:

let suppose the point on Y axis is A

So the A(0,y)

(5,-2) = P

(-3,2)=Q

AP²= AQ²..(Equidistant point)

By distance formula

(0-5)² + [(y-(-2)]²=[(0-(-3)]² + (y-2)²

25+y²+4y+4 = 9+ y²-4y+4

4y +4y=9-25 ......(like term)

8y=-16

y=-16/8

y=-2

A(0,-2)

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Thanks for Question

Therefore the coordinates (5,-2) and (-3,2) is equidistant on Y axis at point (0,-2)