Question

Find the point on y-axis whose distance from point (-8,4) is 10 unit.

Answer 1

Step-by-step explanation:

if the point on y axis then x=0,

so another points are( 0,y)

distance formula=root of (x2-x1)^2+(y2-y1)^2

10=root of (8)^2+(y-4)^2

100=64+y^2+16-8y

y^2-8y-20=0

y^2-10y+2y-20=0

y(y-10)+2(y-10)=0

(y-10)(y+2)=0

y=10,-2

so point is (0,10),( 0,-2)