Question

Find the point onX-axis which is equidistant from A(-3,4) and B(1,-4)​

Answer 1

Answer:

I hope it will be help full for you

Answer 2

Answer:

P(x,y)=(-1,0)

Step-by-step explanation:

A=(-3,4) ;B= (1,-4)

let the point on X-axis be P(x,y)

therefore, by midpoint formula

$x = \frac{ x1 + x2}{2} \\ = \frac{- 3 + 1}{2} \\ = \frac{- 2}{2} \\ x = - 1$

$y = \frac{ y1+ y2 }{2} \\ = \frac{ - 4 + 4}{2} \\ = \frac{0}{2} \\ y = 0$

Therefore,

P(x,y)= (-1,0)