Question

Find the point
stant from
x-axis which is eduidi
points (5,-2), and (-3; 2).​

Answer 1

Answer:

gryth8rfe

$1132222yy > 1y1264 {?}^{?} \times \frac{?}{?} 24 { {)x { \leqslant | {) < < (21161 - 064 \cos( \cot( \beta e) ) \times \frac{?}{?} }^{?} | \times \frac{?}{?} }^{2} }^{2} }^{?}$

bfnigsfi56 was bb

Answer 2

Answer:

Given (3,2) & (-5,-2)

Let the vertex be (x,y)

(x−3)

2

+(y−2)

2

=

(x+5)

2

+(y+2)

2

As the point is on xaxis ∴y=0

⇒(x−3)

2

+(0−2)

2

=(x+5)

2

+(0+2)

2

⇒(x

2

+9−6x)+4=x

2

+25+10x+4

⇒9−6x=25+10x

⇒9−25=(10+6)x

⇒−16=16x

∴ x = -1

Thus point is (-1, 0)

solution