Find the point where line 4x+3y=7 meets x-axis and y axis
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Answered by
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given eq. of line 4x+3y=7..
points at y-axis y=7/3 { at y-axis x becomes 0 }....[ 0,7/4 ]
points at x-axis x = 7/4 { at x-axis y becomes 0 }....[7/5,0]..
hope you understand..
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points at y-axis y=7/3 { at y-axis x becomes 0 }....[ 0,7/4 ]
points at x-axis x = 7/4 { at x-axis y becomes 0 }....[7/5,0]..
hope you understand..
plz mark as brainlist..
Answered by
0
Answer: x coordinate = (7/4,0)
y coordinate = (0,7/3)
Step-by-step explanation:
When line 4x+3y=7 cut the x axis then y = 0 put this in equation we get,
4x+3y=7
4x +0 = 7
x =7/4
So x coordinate = (7/4,0)
When line 4x+3y=7 cut the y axis then x= 0 put this in equation we get
4*0+3y = 7
y = 7/3
so y coordinate = (0,7/3)
dasy31:
Please mark brainly.
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