Question

Find the point where the graph of linear equation 3x+4y=12 cuts the x axis

Answer 1

take x,0
3x+4*0=12
3x=12
x=4
it ll be 4,0

Answer 2

Answer:

-> 4y = 24 -3x

let "x" = 0:

-> 4y = 24 - 3 × 0

-> 4y = 24

-> y = 6

-> (0,6) = Points:

-> Let "x" = 4

-> 4y = 24 - 3 (4)

-> 4y = 24 -12

-> y = 12 / 4

-> y = 3

-> (4,3) = Points:

-> x = -4

-> 4y = 24 - 3v ( -4 )

-> 4y = 24 + 12

-> y = 36 / 4

-> y=9

(-4,9) = Points: