find the point where the graph of the equation 3x +4y=12 cuts (i) x axis (ii) y axis
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Answer: Graph of the equation 3x+4y = 12 cuts x-axis at (4,0) and y - axis at (0,3). Therefore, Graph of the equation 3x+4y = 12 cuts x-axis at (4,0) and y - axis at (0,3).
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