Find the point where the like x+y=6 is a normal to the parabola y.y=8x
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hey mate
here's the solution
here's the solution
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Susmetha:
thank you so much
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Answer:
Step-by-step explanation:
let points be h,k
for tangent use t=0
ky=4h+4x
4x-ky+4h=0
slope of this line = 4/k
slope of normal = -k/4
kx+4y=hk+4k
kx/4 + y = k/4*h+4
comparing with given
k=4
h=2
therefore points 2,4
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