find the point where the line 2x + y - 6 = 0
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2x+6=y
x2+y2−2y−9=0
x2+(2x+6)2−2y−9=0
x2+4x2+36+24x−2y−9=0
5x2+24x+27−2(2x+6)=0
5x2+24x+27−4x−12=0
5x2+20x+15=0
x2+4x+3=0
x2+3x+x+3=0
x(x+3)+1(x+3)=0
(x+3)(x+1)=0
x=−1,−3
y=4,0
So. These points will be Diametrically end's points.
(x+1)(x+3)+(y−4)(y−0)=0
x2+4x+3+y2−4y=0
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