Question

find the point where the line 4x-y+7 =0 interacts x axis​

Answer 1

Answer:

intersection between 4x+2y=7 and y-axis i.e. x=0

put x=0 in 4x+2y=7 ==>. y=7/2

hence point of inersection is (0,7/2)

now unknown equation parellel to y+5=0

slope of unknown line = slope of above line =7

now equation of line

(y-7/2)=7 (x-0)

7x-y+7/2=0

14x-2y+7=0☑️☑️☑️

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Answer 2

Step-by-step explanation:

intersection between 4x+2y=7 and y-axis i.e. x=0

put x=0 in 4x+2y=7

y=7/2

hence point of inersection is (0,7/2)

now unknown equation parellel to

y-7x+5=0

slope of unknown line =slope of above line =7

now equation of line

(y-7/2)=7 (x-0)

7x-y+7/2=0

14x-2y+7=0

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