find the point where the line represented by the equation 5x-3y-10= 0 cuts the y axis
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say x= 0
so 3y =-10
y=-10/3
So,
point is 0,-10/3
so 3y =-10
y=-10/3
So,
point is 0,-10/3
Answered by
0
At x-axis , value of x is 0
put x=0 in equation
5 (0)-3y-10=0
3y=-10
y=-10/3
put x=0 in equation
5 (0)-3y-10=0
3y=-10
y=-10/3
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