Question

find the point which devide the line segment joining the point (7,-6) and (3,4) in ratio 1:2 internally​

Answer 1

Answer:

(17/3,-8/3) is the answer

Answer 2

According to Section Formula :::

x= (mx2+nx1)/m+n

and, y= (my2+ny1)/m+n

therefore, x= {[1x(3)]+[2x(7)]}/1+2

= {3+14}/3

=17/3

and; y= {[1x4]+[2x(-6)]}/1+2

= {4+(-12)}/3

= {4-12}/3

= -8/3

Therefore, (x, y) = (17/3,-8/3)

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