Question

find the point which divides the line segment joining the points (3,5) and (8,10)internally in the ratio 5:6​

Answer 1

Here's the answer buddy

Answer 2

The point which divides the line segment joining the points (3,5) and (8,10)internally in the ratio 5:6 is (5.27,7.27)

Step-by-step explanation:

A=$(x_1,y_1)=(3,5)$

B=$(x_2,y_2)=(8,10)$

Ratio = 5:6

Section formula : $x=(\frac{mx_2+nx_1}{m+n}),y=(\frac{my_2+ny_1}{m+n})$

m:n =5:6

Substitute the values in the formula

$x=(\frac{mx_2+nx_1}{m+n}),y=(\frac{my_2+ny_1}{m+n})\\x=(\frac{5(8)+6(3)}{5+6}),y=(\frac{5(10)+6(5)}{5+6})\\x=5.27,y=7.27$

Hence The point which divides the line segment joining the points (3,5) and (8,10)internally in the ratio 5:6 is (5.27,7.27)

#Learn more :

Find the point which divides the line segment joining the points [3,5]and[8,10]internally in the ratio 2:3

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