Find the point which is dividing the line joining two points in the given ratio.
Answers
Answer:
plz give the points to give you a correct answer, once check it out.
Answer:
Example 1 :
In what ratio does the point P(-2 , 3) divide the line segment joining the points A(-3, 5) and B (4, -9) internally?
Solution :
Given points are (-3 , 5) and B (4 ,- 9).
Let P (-2 , 3) divide AB internally in the ratio l : m By the section formula,
P [ (lx2 + mx1)/(l + m), (ly2 + my1)/(l + m) ] = (-2, 3)
(x1, y1) ==> (-3, 5) and (x2, y2) ==> (4, -9)
(l(4) + m(-3))/(l+m) , (l(-9) + m(5))/(l+m) = (-2, 3)
(4l - 3m)/(l+m), (-9l + 5m)/(l+m) = (-2, 3)
Equating the coefficients of x, we get
(4l - 3m)/(l+m) = -2
4l - 3m = -2(l + m)
4l - 3m = -2l - 2m
Add 2l and 3m on both sides
6l = m
l/m = 1/6
l : m = 1 : 6
Hence the point P divides the line segment joining the points in the ratio 1 : 6.
Example 2 :
Let A (-6,-5) and B (-6, 4) be two points such that a point P on the line AB satisfies AP = (2/9) AB. Find the point P.
Step-by-step explanation:
i hope its helpful :)