Math, asked by pappu8903ss, 4 months ago


Find the point which is dividing the line joining two points in the given ratio.​

Answers

Answered by sreeraaga2506
0

Answer:

plz give the points to give you a correct answer, once check it out.

Answered by marchpaulmarchpaul
0

Answer:

Example 1 :

In what ratio does the point P(-2 , 3) divide the line segment joining the points A(-3, 5) and B (4, -9) internally?

Solution :

Given points are (-3 , 5) and B (4 ,- 9).

Let P (-2 , 3) divide AB internally in the ratio l : m By the section formula,

P [ (lx2 + mx1)/(l + m),  (ly2 + my1)/(l + m) ]  =  (-2, 3)

(x1, y1) ==>  (-3, 5) and (x2, y2) ==>  (4, -9)

(l(4) + m(-3))/(l+m) , (l(-9) + m(5))/(l+m)  =  (-2, 3)

(4l - 3m)/(l+m),  (-9l + 5m)/(l+m)  =  (-2, 3)

Equating the coefficients of x, we get

(4l - 3m)/(l+m)  =  -2

4l - 3m =  -2(l + m)

4l - 3m = -2l - 2m

Add 2l and 3m on both sides

6l  =  m

l/m  =  1/6

l : m  =  1 : 6

Hence the point P divides the line segment joining the points in the ratio 1 : 6.

Example 2 :

Let A (-6,-5) and B (-6, 4) be two points such that a point P on the line AB satisfies AP = (2/9) AB. Find the point P.

Step-by-step explanation:

i hope its helpful :)

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