Question

find the point which lies on the line joining the points (-4,-1) and (-1,2) whose abscissa is -3.

Answer 1

Step-by-step explanation:

$slope \: of \: straight \: line \: = ( - 1 - 2) \div ( - 4 + 1) \\ = > m = 1 = (y - 2) \div (x + 1) \\ = > y = x + 1 + 2 = x + 3$

$so \: the \: line \: is \: y = x + 3$

and given the abscissa of point is -3

=> x = -3

and that point lies on given straight line. So it satisy the equation of line.

then, y = -3+3 = 0