Question

Find the points at which the circle with centre (2,3) and radius 5 units crosses the X-axis

Answer 1

Answer:

(7,0) ,(-3,0)

Step-by-step explanation:

the equation of such circle is (x-2)²+(y-3)²=25

put y=0

(x-2)²=25

x-2=±5

x=7 or x=-3

so the points

(7,0) (-3,0)

Answer 2

Answer:

7,0) ,(-3,0) mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Step-by-step explanation:

the equation of such circle is (x-2)²+(y-3)²=25

put y=0

(x-2)²=25

x-2=±5

x=7 or x=-3

so the points

(7,0) (-3,0)

Step-by-step explanation: