Question

Find the points in which the line segment joining the points ( - 3, - 4 ) and ( 1, - 2 ) is divided by y- axis ?​

Answer 1

Any point on y axis is of the form (0,y)

So let the point be P(0,y) and the ratio of division be k:1



therefore, since k=3
k:1=3:1

Answer 2

Answer:

3 : 1

Step-by-step explanation:

NOTE :

The question will be :

Find the ratio in which the line segment joining the points ( - 3, - 4 ) and ( 1, - 2 ) is divided by y- axis .

Let the ratio be k : 1 .

The sectional formula has to be used in the given problem .

The given points are ( -3 , -4 ) and ( 1, -2 )

$x_1 = -3\\x_2=1\\\\y_1=-4\\y_2=-2$

Since the line is divided by the y-axis , the point will be 0 . y .

Every line on the y - axis has its x-coordinate 0 .

So x = 0 .

By section formula :

$x=\frac{kx_2+x_1}{k+1}\\\\\implies \frac{kx_2+x_1}{k+1}=0\\\\\implies kx_2+x_1=0\\\\\implies k(1)+(-3)=0\\\\\implies k-3=0\\\\\implies k=3$

The ratio is k : 1 .

Hence the answer is 3 : 1 .